php - Trying to compare DateTime objects and its wrong, why? -

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 $dtstart=new datetime($item["start"]["datetime"]);    $dtend  =new datetime($item["end"]["datetime"]);    $dtstgoogle= new datetime($event->start->datetime);    $dtstgoogle->settimezone(new datetimezone("america/chicago"));    $dtendgoogle=new datetime($event->end->datetime);    $dtendgoogle->settimezone(new datetimezone("america/chicago"));    $dtdiffstart=$dtstart->diff($dtstgoogle);    $dtdiffend=$dtend->diff($dtendgoogle);

i using php 5.6.13 , 5.6.14 try compare them , result either true or false regardless of value.

  if ($dtdiffend) { printf("<br> start date time different %d %d %d  %d %d %d ",$dtdiffstart->m,$dtdiffstart->d,$dtdiffstart->y,$dtdiffstart->h,$dtdiffstart->m,$dtdiffstart->s);}   incorrect   if (!$dtdiffend) { same above} incorrect   if ($dtstart!=$dtstartgoogle) {same above} incorrect   if ($dtstart!==$dtstartgoogle) {same above} incorrect

either results values of 0 0 0 0 0 0 (always true) or none (always false) @ , both incorrect. have tried other crazy things same results.

i have tried can think of, know doing wrong?

this works, there has got simplier way:

if ((($dtdiffend->m!=0) || ($dtdiffend->d!=0) || ($dtdiffend->y!=0) || ($dtdiffend->h!=0) || ($dtdiffend->i!=0) || ($dtdiffend->s!=0)))

any advice appreciated.

$dtdiffstart=$dtstart->diff($dtstgoogle); $dtdiffend=$dtend->diff($dtendgoogle);

are 2 instances of dateinterval, it'll considered true.

if ($dtstart!=$dtendgoogle)

in case return true, 2 datetime instances different (different timezone)

if want check if $dtstart , $dtendgoogle different, do:

($dtstart->format('u') != $dtendgoogle->format('u'))

'u' used unix timestamp. can change format depending on needs.


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