Get folder name of the file in Python -

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in python command should use name of folder contains file i'm working with?

"c:\folder1\folder2\filename.xml"

here "folder2" want get.

the thing i've come use os.path.split twice:

foldername = os.path.split(os.path.split("c:\folder1\folder2\filename.xml")[0])[1]

is there better way it?

you can use dirname:

os.path.dirname(path)

return directory name of pathname path. first element of pair returned passing path function split().

and given full path, can split last portion of path. example, using basename:

os.path.basename(path)

return base name of pathname path. second element of pair returned passing path function split(). note result of function different unix basename program; basename '/foo/bar/' returns 'bar', basename() function returns empty string ('').

all together:

>>> import os >>> path=os.path.dirname("c:/folder1/folder2/filename.xml") >>> path 'c:/folder1/folder2' >>> os.path.basename(path) 'folder2'

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