java - How does the values of an array changes when we passed it as an argument to other function? -

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when passed array argument function, original array gets changed, array should not changed right? please correct me if wrong.

below passed int x=10 argument change(int a) function. value of original int x got changed.

so how same code affects array , int in different way?

public  class runy  {  public static void main(string [] args)  {     runy p = new runy();     p.start(); }  void start()  {     long [] a1 = {3,4,5};     long [] a2 = fix(a1);      int x=10;     int y= change(x);      system.out.println(y);     system.out.println(x);      system.out.print(a1[0] + a1[1] + a1[2] + " ");     system.out.println(a2[0] + a2[1] + a2[2]);  }  long [] fix(long [] a3)  {     a3[1] = 7;     return a3; } int change(int a) {     a=a+1;     return a; } 

}

you're wrong. you're passing in isn't array - it's reference array. arrays reference types in java, value of a1 (for example) isn't array object - it's reference array object.

when pass reference fix, parameter (a3) has same value a1... value refers same array, modification array visible after method returns. @ point, a1 , a2 equal references - both refer same array.