python - list indices must be integers, not str error -

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with little function here, trying change 10 digit integer phone number word form. gives me error.

def getwordform(phone_num):     cake=list(phone_num)     print(cake)     v in cake:         if cake[v] == 0:             cake[v] = "zero "         elif cake[v] == 1:             cake[v] = "one "         elif cake[v] == 2:             cake[v] = "two "         elif cake[v] == 3:             cake[v] = "three "         elif cake[v] == 4:             cake[v] = "four "                 elif cake[v] == 5:             cake[v] = "five "           elif cake[v] == 6:             cake[v] = "six "         elif cake[v] == 7:             cake[v] = "seven "         elif cake[v] == 8:             cake[v] = "eight "         elif cake[v] == 9:             cake[v] = "nine "

thanks everyone.

you're iterating on list of 1-character strings, , trying find out if list's element @ string index equal integer. i'll demonstrate why that's near need replacing variables literals:

def getwordform('1234567890'):     ['1', '2', '3', '4', '5', '6', '7', '8', '9', '0']=list('1234567890')     print(['1', '2', '3', '4', '5', '6', '7', '8', '9', '0'])     '1','2',etc. in ['1', '2', '3', '4', '5', '6', '7', '8', '9', '0']:         if cake['1'] == 0:             cake['1'] = "zero "

you have index list integers. characters in phone number (which happen represent integers) have nothing index - have '9' @ index 3. aren't returning anything, function run (if could), end, , throw away.

do instead:

def getwordform(phone_num):     numbers = {'0':'zero', '1':'one', '2':'two', '3':'three', '4':'four',                '5':'five', '6':'six', '7':'seven', '8':'eight', '9':'nine'}     return ' '.join(numbers[num] num in phone_num)

the result expected:

>>> getwordform('123') 'one 2 three'

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