Awk calculation rounding output to integers -

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i have calculation , need it's output whole number, might return 1 desimals.

echo $((ram/50)) | awk '{printf( "%.0f\n", $1*0.$1 )}'

so, ram/50, in case, returns 36, piped awk. want awk multiply number 0.the number itself, so: 36*0.36. return 12.96, want rounded 13. command now, 36*0.36 calculation doesn't work , printf removes .96, dosen't round off.

your problem related operator precedence. multiplication higher precedence string concatenation, need parentheses in order make work expect:

echo 36 | awk '{ printf "%.0f\n", $1 * ("0." $1) }'

in version, order of operations means you're multiplying field 1 0, concatenating field 1, before passing result printf.


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