r - reorder facets by multiple variables in ggplot -

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i have data frame following column names/header:

 date         time              id            datetime    site  origin           species         genus    sex pp repro

i trying ggplot faceted figure y-axis being of "id"s, in order of "sex" , in order of "repro"... ideally female "ids" @ top , in order of repro status, , under male "ids", grouped repro status (females - pregnant, females - non pregnant, males - reproducing, males -non - in order). ggplot code looks currently:

    presence<-ggplot(data, aes(x=date,y=reorder(sex,repro)))+   geom_point(aes(x=date,y=presence,colour=sex))+facet_grid(id~.)+   theme()+   ylab("\n")+   theme(legend.position="none",         axis.text.y= element_blank(),         strip.text.y=element_text(angle=0))

reordering 2 variables here didn't work...

in case useful... here's more information dput:

    structure(list(date = structure(c(16439, 16439, 16443, 16444,  16444, 16445), class = "date"), time = c("05:11:00.470", "19:41:08.120",  "20:45:38.570", "22:27:59.370", "22:53:13.370", "18:44:49.630" ), id = c("989001000312244", "989001000312244", "989001000312214",  "989001000312285", "989001000312285", "989001000312252"), datetime =    structure(list(     sec = c(0.47, 8.12, 38.57, 59.37, 13.37, 49.63), min = c(11l,      41l, 45l, 27l, 53l, 44l), hour = c(5l, 19l, 20l, 22l, 22l,      18l), mday = c(4l, 4l, 8l, 9l, 9l, 10l), mon = c(0l, 0l,      0l, 0l, 0l, 0l), year = c(115l, 115l, 115l, 115l, 115l, 115l     ), wday = c(0l, 0l, 4l, 5l, 5l, 6l), yday = c(3l, 3l, 7l,      8l, 8l, 9l), isdst = c(0l, 0l, 0l, 0l, 0l, 0l), zone = c("pst",      "pst", "pst", "pst", "pst", "pst"), gmtoff = c(na_integer_,      na_integer_, na_integer_, na_integer_, na_integer_, na_integer_     )), .names = c("sec", "min", "hour", "mday", "mon", "year",  "wday", "yday", "isdst", "zone", "gmtoff"), class = c("posixlt",  "posixt")), site = c("chivato", "chivato", "chivato", "chivato",  "chivato", "chivato"), origin = structure(c(2l, 2l, 2l, 2l, 2l,  2l), .label = c("carmen", "chivato", "la capilla", "las cuevas",  "lto1"), class = "factor"), species = structure(c(2l, 2l, 2l,  2l, 2l, 2l), .label = c("californicus", "yerbabuenae"), class = "factor"),      genus = structure(c(1l, 1l, 1l, 1l, 1l, 1l), .label = c("leptonycteris",      "macrotus"), class = "factor"), sex = structure(c(1l, 1l,      2l, 2l, 2l, 2l), .label = c("female", "male", "unrecorded"     ), class = "factor"), pp = c(1, 1, 1, 1, 1, 1), repro = structure(c(2l,      2l, 2l, 2l, 2l, 2l), .label = c("lactating", "non", "postlactating",      "pregnant", "testes"), class = "factor")), .names = c("date",  "time", "id", "datetime", "site", "origin", "species", "genus",  "sex", "pp", "repro"), row.names = c(846l, 878l, 1101l, 1152l,  1154l, 1185l), class = "data.frame")

the comment left @aosmith point in right direction. here example based on larger simulated data set.

library(ggplot2) library(dplyr)  # create , example data set set.seed(42) plot_data <-    data.frame(date  = lubridate::ymd("2015-10-01") + lubridate::days(0:30),               sex   = factor(sample(c("male", "female"), 31, replace = true), levels = c("female", "male")),              repro = factor(sample(c("reproducing", "non-reproducing"), 31, replace = true), levels = c("reproducing", "non-reproducing")),               pp    = 1,              id    = factor(1:31))  # arrange data set sex , repro status,  relevel id factor # such levels in opposite order of arranged data.frame. # allow order expected in following plot. plot_data <-    plot_data %>%    arrange(sex, repro) %>%   mutate(id = factor(id, levels = rev(id)))  ggplot(plot_data) +    theme_bw() +    aes(x = date, y = id, color = sex, shape = repro) +   geom_point(size = 3) +    ylab("subject id") +    xlab("date") +    theme(legend.position = "bottom")

enter image description here


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