python - Need assistance on final bit of script if possible -

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here prequisites script

"generate string n opening brackets ("[") , n closing brackets     ("]"), in arbitrary order. need use random numbers. determine whether generated string balanced; is, whether     consists entirely of pairs of opening/closing brackets (in order), none of mis-nest. examples:  [] ok ][ not ok [][] ok ][][ not ok [[][]] ok []][[] not ok

"

i have come , thought done, reliased doesnt quite on line because positive result "[]]["

can me achieving part "pairs of opening/closing brackets (in order),"

#!/usr/bin/python   import string import random   def brackets(): count = 0   sample = [random.choice(['[', ']', '[]']) _ in range(random.randint(1, 10))]  sample2 =''.join([random.choice(['[', ']', '[]']) _ in range(random.randint(1, 10))])   count1 = sample2.count('[') count2 = sample2.count(']')   x in sample2:      if x == "[":         count +=1      if x == "]":         count -=1  if count != 0 or count < 0 :     print "the generated sample %s " % (sample2,)     print "there %d [ in generated string" % (count1,)     print "there %d ] in generated string" % (count2,)     print "this string not ok"   if count == 0 :     print "the generated sample %s " % (sample2,)     print "there %d [ in generated string" % (count1,)     print "there %d ] in generated string" % (count2,)     print "this string ok"    print brackets()

here's funny little idea had. works seeing whether or not bracket pairs can turned individual lists:

from ast import literal_eval  def valid(s):     if any(c not in '[]' c in s): return false     try:         literal_eval(s.replace('[]', '[],'))         return true     except syntaxerror:         return false

this (i believe) should work every time, including examples gave:

>>> valid('[]') true >>> valid('][') false >>> valid('[][]') true >>> valid('][][') false >>> valid('[[][]]') true >>> valid('[]][[]') false

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